String Matching in an Array

Given an array of string words, return all strings in words that are a substring of another word. You can return the answer in any order.

 

Example 1:

Input: words = ["mass","as","hero","superhero"]
Output: ["as","hero"]
Explanation: "as" is substring of "mass" and "hero" is substring of "superhero".
["hero","as"] is also a valid answer.

 

Example 2:

Input: words = ["leetcode","et","code"]
Output: ["et","code"]
Explanation: "et", "code" are substring of "leetcode".

 

Example 3:

Input: words = ["blue","green","bu"]
Output: []
Explanation: No string of words is substring of another string.

 

 

Solution

class Solution:
    def stringMatching(self, words: List[str]) -> List[str]:
        words.sort(key=len)
        answer = []

        for i in range(len(words)):
            for j in range(i+1, len(words)):
                if words[i] in words[j]:
                    answer.append(words[i])
                    break

        return answer